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常用导数,积分以及等价无穷小

这一串是不太熟的

(tan⁡x)′=sec⁡2x(cot⁡x)′=−csc⁡2x(sec⁡x)′=sec⁡xtan⁡x(csc⁡x)′=−csc⁡xcot⁡x(ax)′=axln⁡a(log⁡ax)′=1xln⁡a(arcsin⁡x)′=11−x2(arccos⁡x)′=−11−x2(arctan⁡x)′=11+x2(\arccotx)′=−11+x2\begin{align} &(\tan x)'=\sec^2x \\ &(\cot x)'=-\csc^2x \\ &(\sec x)'=\sec x\tan x \\ &(\csc x)'=-\csc x\cot x \\ &(a^x)'=a^x\ln a \\ &(\log_a x)'=\frac{1}{x\ln a} \\ \\ &(\arcsin x)'=\frac{1}{\sqrt{1-x^2}} \\ &(\arccos x)'=-\frac{1}{\sqrt{1-x^2}} \\ &(\arctan x)'=\frac{1}{1+x^2}\\ &(\arccot x)'=-\frac{1}{1+x^2} \end{align}

在特殊情况时,这些可以相互替换……

lim⁡x→0x=ln⁡(1+x)=ex−1=arctan⁡x=sin⁡x=arcsin⁡x=tan⁡x\lim_{x \to 0} x=\ln(1+x)=e^x-1=\arctan x=\sin x=\arcsin x=\tan x lim⁡x→01−cos⁡x=sec⁡x−1=12x2\lim_{x\to0}1-\cos x=\sec x-1=\frac{1}{2}x^2 lim⁡x→01+xn−1=(1+x)1n−1=1nx\lim_{x\to0} \sqrt[n]{1+x}-1=(1+x)^{\frac{1}{n}}-1=\frac{1}{n}x ex=1+x+x22!+⋯+xnn!+eθx(n+1)!xn+1e≈1+1+12!⋯+1n!sin⁡x=x−x33!+x55!−⋯cos⁡x=1−12!x2+14!x4−⋯11+x=1−x+x2−x3+⋯+(−1)nxn+⋯(1+x)a=1+ax+a(a−1)2!x2+⋯+a(a−1)⋯(a−n+1)n!xn+O(xn)\begin{align} &e^x=1+x+\frac{x^2}{2!} + \cdots +\frac{x^n}{n!}+\frac{e^{\theta x}}{(n+1)!}x^{n+1} \\ &e \approx 1+1+\frac{1}{2!}\cdots + \frac{1}{n!} \\ &\sin x = x-\frac{x^3}{3!} + \frac{x^5}{5!} - \cdots \\ &\cos x = 1-\frac{1}{2!}x^2+\frac{1}{4!}x^4- \cdots \\ &\frac{1}{1+x} = 1-x+x^2-x^3+\cdots+(-1)^nx^n+\cdots \\ &(1+x)^a=1+ax+\frac{a(a-1)}{2!}x^2+\cdots+\frac{a(a-1)\cdots(a-n+1)}{n!}x^n+O(x^n) \\ & \end{align}

这些还是要背的,(1)(1)的绝对值很重要

∫1x dx=ln⁡∣x∣+C∫11+x2 dx=arctan⁡(x)+C∫11−x2 dx=arcsin⁡x+C∫1cos⁡2x dx=∫sec⁡2x dx=tan⁡x+C∫1sin⁡2x dx=∫csc⁡2x dx=−cot⁡x+C∫sec⁡xtan⁡x dx=sec⁡x+C∫csc⁡xcot⁡x dx=−csc⁡x+C∫sec⁡x dx=ln⁡∣sec⁡x+tan⁡x∣+C∫csc⁡x dx=ln⁡∣csc⁡x−cot⁡x∣+C\begin{align} &\int \frac{1}{x}\,dx = \ln|x| + C \tag 1 \\ &\int \frac{1}{1+x^2}\,dx = \arctan(x) + C \tag2 \\ &\int \frac{1}{\sqrt{1-x^2}}\,dx = \arcsin x + C \tag3 \\ &\int \frac{1}{\cos^2x}\,dx = \int \sec^2 x\,dx = \tan x + C \tag4 \\ &\int \frac{1}{\sin^2x}\,dx = \int \csc^2 x\,dx = -\cot x + C \tag5 \\ &\int \sec x\tan x\,dx = \sec x + C \tag6 \\ &\int \csc x\cot x\,dx = -\csc x+ C \tag7 \\ \\ \\ &\int \sec x\,dx = \ln|\sec x+\tan x| + C \tag8 \\ &\int \csc x\,dx = \ln|\csc x-\cot x| + C \tag9 \end{align}

(8)(8)和(9)(9)是应该记一下的,唉三角函数

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